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Suppose we have a list of numbers called nums, we have to find the length of longest subsequence that flips sign on each consecutive number.

So, if the input is like nums = [1, 3, -6, 4, -3], then the output will be 4, as we can pick [1, -6, 4, -3].

To solve this, we will follow these steps −

- pos := 0, neg := 0
- for each n in nums, do
- if n < 0, then
- neg := pos + 1

- otherwise,
- pos := neg + 1

- if n < 0, then
- return maximum of pos and neg

Let us see the following implementation to get better understanding −

class Solution: def solve(self, nums): pos = neg = 0 for n in nums: if n < 0: neg = pos + 1 else: pos = neg + 1 return max(pos, neg) ob = Solution() nums = [1, 3, -6, 4, -3] print(ob.solve(nums))

[1, 3, -6, 4, -3]

4

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